What’s up friends?!?<\/p>\n
Let’s continue on another linear linked list problem. I’m going to make this post short since I’ll use the boilerplate code from the last LLL problem we had. If you need any help, I’ll also post the link to GitHub so you can stroll along.<\/p>\n
Anyways, for this problem, I just want to write some code to find a specific element inside the LLL. You could do this iteratively or recursively, whichever way you choose to do, but for the purpose of this program, I am just going to solve it iteratively.<\/p>\n
<\/p>\n
\r\n # searching iteratively function\r\n def searchElement(self, number):\r\n\r\n # default case if there's no list in the first place\r\n if not self.head:\r\n return False\r\n\r\n current = self.head\r\n\r\n # going through the linked list\r\n while current is not None:\r\n if current.data == number:\r\n return True\r\n current = current.next\r\n\r\n return False\r\n<\/pre>\nI’d say the most important here is to notice how I used the while loop to go through each of the node, and use the pointers to point to the next node. It would exit out of the loop if the data of the current node doesn’t exist.<\/p>\n
Well, if you have any question, feel free to ask and have a great day.<\/p>\n
<\/p>\n","protected":false},"excerpt":{"rendered":"
What’s up friends?!? Let’s continue on another linear linked list problem. I’m going to make this post short since I’ll use the boilerplate code from the last LLL problem we had. If you need any help, I’ll also post the link to GitHub so you can stroll along. Anyways, for this problem, I just want … <\/p>\n